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प्रश्न
Draw an ∠ABC = 60°, having AB = 4.6 cm and BC = 5 cm. Find a point P equidistant from AB and BC; and also equidistant from A and B.
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उत्तर
Steps of construction:
- Draw a line segment BC = 5 cm
- At B, draw a ray BX making an angle of 60° and cut off BA = 4.6 cm.
- Draw the angle bisector of ∠ABC.
- Draw the perpendicular bisector of AB which intersects the angle bisector at P.
P is the required point which is equidistant from AB and BC, as well as from A and B.
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संबंधित प्रश्न
Construct a triangle ABC, in which AB = 4.2 cm, BC = 6.3 cm and AC = 5 cm. Draw perpendicular bisector of BC which meets AC at point D. Prove that D is equidistant from B and C.
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