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प्रश्न
`(sec^2 theta -1)(cosec^2 theta - 1)=1`
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उत्तर
LHS = `(sec^2 theta -1)(cosec^2 theta-1)`
=`tan^2 theta xx cot^2 theta ( ∵ sec^2 theta - tan^2 theta = 1 and cosec^2 theta - cot^2 theta =1)`
=` tan^2 theta xx1/(cos^2theta)`
=1
=RHS
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संबंधित प्रश्न
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Activity:
L.H.S. = `square`
= `square (1 - (sin^2θ)/(tan^2θ))`
= `tan^2θ (1 - square/((sin^2θ)/(cos^2θ)))`
= `tan^2θ (1 - (sin^2θ)/1 xx (cos^2θ)/square)`
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