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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Representation of the Results of a Chemical Change – is a Chemical Equation. Answer the Following: What is the Indications of the Arrow Between the Reactants and the Products and

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प्रश्न

Representation of the results of a chemical change – is a chemical equation.

For the equation: FeCl3 + 3NH4OH 3NH4Cl + Fe(OH)3 ↓

Answer the following:

What is the indications of the arrow between the reactants and the products and of the arrow pointing downwards at the end.

टीपा लिहा
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उत्तर

  1. The function of the arrow(→)between the reactants & products is that it represents the chemical reaction taken place between two reactants.
  2. Arrow pointing downwards (↓) at the end shows the precipitate formed in the chemical equation.
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पाठ 5: Language of Chemistry - Exercise

संबंधित प्रश्‍न

Complete and balance the following equation:

NaOH + .......... \[\ce{-> Na2SO4 + H2O}\]


Write a complete balanced equation for the following reaction:

\[\ce{Sulphur dioxide (gas) + Oxygen (gas) -> Sulphur trioxide (gas)}\]


Balance the following chemical equation:

\[\ce{MnO2 + HCl -> MnCl2 + Cl2 + H2O}\]


While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:


Complete the following equation:

CH3COOH + NaOH → 


Write down what you understood from the following chemical reaction.

AgNO3(aq) + NaCI(aq) → AgCI ↓ + NaNO3(aq)


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\[\ce{2H2O ->[electric][current] 2H2 + O2}\]


Balance the following simple equation:

H2   +   Cl2  →  HCl


Underline the compound in the equation given below, it is incorrectly balanced and write the correct balancing for the same.

Cl2 + 2H2O + SO2 → 4HCl + H2SO4


Write the skeleton equation for the following word equation and then balance them.

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  3. Sulphur + Oxygen → Sulphur dioxide.
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