Question

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate moles of acid required.

Answer 1

1 mole MnO₂ requires HCl = 4 mole

So, 0.02 mole MnO₂ will require = 4 × 0.02

= 0.08 mole