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प्रश्न
Ray optics is based on the assumption that light travels in a straight line. Diffraction effects (observed when light propagates through small apertures/slits or around small obstacles) disprove this assumption. Yet the ray optics assumption is so commonly used in understanding location and several other properties of images in optical instruments. What is the justification?
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उत्तर
The justification is that in ordinary optical instruments, the size of the aperture involved is much larger than the wavelength of the light used.
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संबंधित प्रश्न
Estimate the distance for which ray optics is good approximation for an aperture of 4 mm and wavelength 400 nm.
In a single slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band?
In a single slit diffraction experiment, when tiny circular obstacle is placed in path of light from a distance source, a bright spot is seen at the centre of the shadow of the obstacle. Explain why?
State two points of difference between the interference patterns obtained in Young’s double slit experiment and the diffraction pattern due to a single slit.
Will the diffraction effects from a slit be more or less clearly visible if the slit-width is increased?
In a single slit diffraction experiment, the width of the slit is increased. How will the
- size and
- intensity
of central bright band be affected? Justify your answer.
What is diffraction when light passes through a single narrow slit?
What are LN and M in the single-slit experimental setup?
Where is the screen placed in the single-slit experimental setup?
What appears at the centre of the single-slit diffraction pattern?
At \[\theta=0\], how do the distances from the secondary sources to point C compare?
Why is point C the brightest point of the single-slit diffraction pattern?
What is the path difference between rays from the top and middle of a slit of width \[a\]?
Which equation equates the top-to-middle path difference to the value required for destructive interference?
What condition for a dark fringe follows from \[\frac{a}{2}\sin\theta=\frac{\lambda}{2}\]?
Into how many equal parts can the slit be divided to generalise the condition for minima?
Why are secondary maxima much weaker than the central maximum?
