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प्रश्न
Which equation equates the top-to-middle path difference to the value required for destructive interference?
पर्याय
\[a\sin\theta=\frac{\lambda}{2}\]
\[\frac{a}{2}\sin\theta=0\]
\[\frac{a}{2}\sin\theta=\lambda\]
\[\frac{a}{2}\sin\theta=\frac{\lambda}{2}\]
MCQ
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उत्तर
The top-to-middle path difference is \[\frac{a}{2}\sin\theta\]. Setting it equal to \[\frac{\lambda}{2}\] makes corresponding rays cancel.
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
