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प्रश्न
Rationalise the denominator of the following:
`3/(2sqrt5)`
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उत्तर
We know that rationalization factor for `1/sqrta`is `sqrta`. We will multiply numerator and denominator of the given expression `3/(2sqrt5)` by `sqrt5`to get
`3/(2sqrt5) xx sqrt5/sqrt5 = (3sqrt5)/(2sqrt5 xx sqrt5)`
`= (3sqrt5)/(2xx5)`
`= (3sqrt5)/10`
Hence the given expression is simplified to `(3sqrt5)/10`
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संबंधित प्रश्न
Simplify of the following:
`root(3)4 xx root(3)16`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Rationales the denominator and simplify:
`(5 + 2sqrt3)/(7 + 4sqrt3)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
If\[\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = x + y\sqrt{3},\] find the values of x and y.
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
