मराठी

Prove the statement by using the Principle of Mathematical Induction: n2 < 2n for all natural numbers n ≥ 5.

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प्रश्न

Prove the statement by using the Principle of Mathematical Induction:

n2 < 2n for all natural numbers n ≥ 5.

सिद्धांत
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उत्तर

P(n) is n2 < 2n for n ≥ 5.

Let P(k) = k2 < 2k be true.

⇒ P(k + 1) = (k + 1)2

= k2 + 2k + 1

2k+1 = 2(2k) > 2k2

Since, n2 > 2n + 1 for n ≥ 3.

We get that,

k2 + 2k + 1 < 2k2

⇒ (k + 1)2 < 2(k+1)

⇒ P(k + 1) is true when P(k) is true.

Therefore, by Mathematical Induction, P(n) = n2 < 2n is true for all natural numbers n ≥ 5.

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पाठ 4: Principle of Mathematical Induction - Exercise [पृष्ठ ७१]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 4 Principle of Mathematical Induction
Exercise | Q 11 | पृष्ठ ७१

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