मराठी

Prove the statement by using the Principle of Mathematical Induction: 1 + 5 + 9 + ... + (4n – 3) = n(2n – 1) for all natural numbers n.

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प्रश्न

Prove the statement by using the Principle of Mathematical Induction:

1 + 5 + 9 + ... + (4n – 3) = n(2n – 1) for all natural numbers n.

सिद्धांत
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उत्तर

Let P(n) : 1 + 5 + 9 + … + (4n – 3) = n(2n – 1), for all natural numbers n.

P(1): 1 = 1(2 × 1 – 1) = 1, which is true.

Hence, P(1) is true.

Let us assume that P(n) is true for some natural number n = k.

∴ P(k) : 1 + 5 + 9 + … + (4k – 3) = k(2k – 1)   .......(i)

Now, we have to prove that P(k + 1) is true.

P(k + 1) : 1 + 5 + 9 + … + (4k – 3) + [4(k + 1) – 3]

= 2k2 – k + 4k + 4 – 3

= 2k2 + 3k + 1

= (k + 1)( 2k + 1)

= (k + 1)[2(k + 1) – 1]

Hence, P(k + 1) is true whenever P(k) is true.

So, by the principle of mathematical induction P(n) is true for any natural number n.

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पाठ 4: Principle of Mathematical Induction - Exercise [पृष्ठ ७१]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 4 Principle of Mathematical Induction
Exercise | Q 16 | पृष्ठ ७१

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