Advertisements
Advertisements
प्रश्न
Prove the following identities:
(sec A – cos A) (sec A + cos A) = sin2 A + tan2 A
Advertisements
उत्तर
L.H.S. = (sec A – cos A) (sec A + cos A)
= sec2 A – cos2 A
= (1 + tan2 A) – (1 – sin2 A)
= sin2 A + tan2 A
= R.H.S.
APPEARS IN
संबंधित प्रश्न
`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`
` (sin theta + cos theta )/(sin theta - cos theta ) + ( sin theta - cos theta )/( sin theta + cos theta) = 2/ ((1- 2 cos^2 theta))`
cos4 A − sin4 A is equal to ______.
Prove the following identity :
sinθcotθ + sinθcosecθ = 1 + cosθ
If tan A + sin A = m and tan A − sin A = n, then show that `m^2 - n^2 = 4 sqrt (mn)`.
Prove that: `1/(cosec"A" - cot"A") - 1/sin"A" = 1/sin"A" - 1/(cosec"A" + cot"A")`
If 5x = sec θ and `5/x` = tan θ, then `x^2 - 1/x^2` is equal to
cos θ . sec θ = ?
If `cos θ = 24/25`, then sin θ = ?
If sinA + sin2A = 1, then the value of the expression (cos2A + cos4A) is ______.
