Advertisements
Advertisements
प्रश्न
Prove the following identities:
(sec A – cos A) (sec A + cos A) = sin2 A + tan2 A
Advertisements
उत्तर
L.H.S. = (sec A – cos A) (sec A + cos A)
= sec2 A – cos2 A
= (1 + tan2 A) – (1 – sin2 A)
= sin2 A + tan2 A
= R.H.S.
संबंधित प्रश्न
Prove the following trigonometric identities
sec4 A(1 − sin4 A) − 2 tan2 A = 1
Prove the following identities:
(cosec A – sin A) (sec A – cos A) (tan A + cot A) = 1
` tan^2 theta - 1/( cos^2 theta )=-1`
From the figure find the value of sinθ.
\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to
If cos (\[\alpha + \beta\]= 0 , then sin \[\left( \alpha - \beta \right)\] can be reduced to
Prove the following identities:
`(sec"A"-1)/(sec"A"+1)=(sin"A"/(1+cos"A"))^2`
Find the value of x , if `cosx = cos60^circ cos30^circ - sin60^circ sin30^circ`
Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A.
Let x1, x2, x3 be the solutions of `tan^-1((2x + 1)/(x + 1)) + tan^-1((2x - 1)/(x - 1))` = 2tan–1(x + 1) where x1 < x2 < x3 then 2x1 + x2 + x32 is equal to ______.
