मराठी

Prove that: cos 6 A − sin 6 A = cos 2 A ( 1 − 1 4 sin 2 2 A )

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प्रश्न

Prove that: \[\cos^6 A - \sin^6 A = \cos 2A\left( 1 - \frac{1}{4} \sin^2 2A \right)\]

 
संख्यात्मक
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उत्तर

\[LHS = \cos^6 A - \sin^6 A\]

\[ = \left( \cos^2 A \right)^3 - \left( \sin^2 A \right)^3 \]

\[ = \left( \cos^2 A - \sin^2 A \right)\left( \cos^4 A + \sin^2 A . \cos^2 A + \sin^4 A \right)\]

\[= \cos2A\left( \cos^4 A + 2 \sin^2 A \cos^2 A + \sin^4 A - \sin^2 A \cos^2 A \right)\]

\[ = \cos2A\left\{ \left( \sin^2 A + \cos^2 A \right)^2 - \frac{1}{4} \times 4 \sin^2 A \cos^2 A \right\}\]

\[= \cos2A\left\{ \left( \sin^2 A + \cos^2 A \right)^2 - \frac{1}{4} \left( 2\text{ sin } A\text{ cos } A \right)^2 \right\}\]

\[ = \cos2A\left\{ 1 - \frac{1}{4} \left( \sin2A \right)^2 \right\}\]

\[ = \cos2A\left\{ 1 - \frac{1}{4} \sin^2 2A \right\} = RHS\]

\[\text{ Hence proved } .\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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पाठ 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.1 [पृष्ठ २८]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.1 | Q 21 | पृष्ठ २८

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