मराठी

The value of sin π18+sin π9+sin 2π9+sin 5π18 is given by ______. - Mathematics

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प्रश्न

The value of `sin  pi/18 + sin  pi/9 + sin  (2pi)/9 + sin  (5pi)/18` is given by ______.

पर्याय

  • `sin  (7pi)/18 + sin  (4pi)/9`

  • 1

  • `cos  pi/6 + cos  (3pi)/7`

  • `cos  pi/9 + sin  pi/9`

MCQ
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उत्तर

The value of `sin  pi/18 + sin  pi/9 + sin  (2pi)/9 + sin  (5pi)/18` is given by `sin  (7pi)/18 + sin  (4pi)/9`.

Explanation:

The given expression is `sin  pi/18 + sin  pi/9 + sin  (2pi)/9 + sin  (5pi)/18`

= `(sin  (5pi)/18 + sin  pi/18) + (sin  (2pi)/9 + sin  pi/9)`

= `2sin (((5pi)/18 + pi/18)/2) * cos (((5pi)/18 - pi/18)/2) + 2sin (((2pi)/9 + pi/9)/2)*cos(((2pi)/9 - pi/9)/2)`

= `2sin  pi/6 * cos  pi/9 + 2sin  pi/6* cos  pi/18`

= `2 xx 1/2 cos  pi/9 + 2 xx 1/2 cos  pi/18`

= `cos  pi/9 + cos  pi/18`

= `sin(pi/2 - pi/9) + sin(pi/2 - pi/18)`

= `sin  (7pi)/18 + sin  (8pi)/18`

= `sin  (7pi)/18 + sin  (4pi)/9`

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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पाठ 3: Trigonometric Functions - Exercise [पृष्ठ ५८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
Exercise | Q 54 | पृष्ठ ५८

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