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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

Power of a lens is – 4D, then its focal length is

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प्रश्न

Power of a lens is – 4D, then its focal length is

पर्याय

  • 4m

  • –40m

  • –0.25 m

  • –2.5 m

MCQ
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उत्तर

– 0.25 m

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पाठ 2: Optics - Evaluation [पृष्ठ २९]

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सामाचीर कलवी Science [English] Class 10 SSLC TN Board
पाठ 2 Optics
Evaluation | Q I. 6. | पृष्ठ २९

संबंधित प्रश्‍न

(a) At what distance should the lens be held from the figure in order to view the squares distinctly with the maximum possible magnifying power?

(b) What is the magnification in this case?

(c) Is the magnification equal to the magnifying power in this case? Explain.


You have two lenses A and B of focal lengths +10 cm and –10 cm, respectively. State the nature and power of each lens. Which of the two lenses will form a virtual and magnified image of an object placed 8 cm from the lens? Draw a ray diagram to justify your answer


What can you see in a completely dark room? If you switch on an electric bulb in this dark room as a light source, explain how you could now see:
(a) the electric bulb
(b) a piece of white paper


How is the power of a lens related to its focal length?


Define power of a lens. What is its unit? One student uses a lens of focal length 50 cm and another of –50 cm. What is the nature of the lens and its power used by each of them?


An object is placed in front of a converging lens. Obtain the conditions under which the magnification produced by the lens is

  1. negative and
  2. positive.

When monochromatic red light is used instead of blue light in a convex lens, its focal length will ______.


A positive power of a lens indicates a:


A concave lens has:


For a lens with \[f = +12\,cm\], \[R_1 = +10\,cm\] and \[R_2 = -15\,cm\], the lens maker's formula \[\frac{1}{f}=(n-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)\] gives the refractive index of the glass as:


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