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प्रश्न
Potassium (Atomic No. 19) and chlorine (Atomic No. 17) react to form a compound. On the basis of electronic concept, explain
(i) oxidation
(ii) reduction
(iii)oxidising agent
(iv)reducing agent
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उत्तर
2K + Cl2→ 2KCl
1.Oxidation: In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).
K → K+ + e-
2.Reduction: In the electronic concept, the reduction is a process in which an atom or ion accepts electron(s).
Cl2 + 2e-→ 2Cl-
iii. Oxidising agent
An oxidising agent oxidises other substances either by accepting electrons or by providing oxygen or an electronegative ion, or by removing hydrogen or an electropositive ion.
Cl2 + 2e-→ 2Cl-
iv.Reducing agent
A reducing agent reduces other substances either by providing electrons or by providing hydrogen or an electropositive ion, or by removing oxygen or an electronegative ion.
K → K+ + e-
संबंधित प्रश्न
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(a) P and R
(b) Q and S
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(d) R and S
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C3H4
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The I.U.P.A.C name of CH3CH2CH = CH2 is?
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