Advertisements
Advertisements
प्रश्न
Modulus of rigidity of ideal liquids is ______.
पर्याय
infinity.
zero.
unity.
some finite small non-zero constant value.
Advertisements
उत्तर
Modulus of rigidity of ideal liquids is zero.
Explanation:
Modulus of Rigidity: Within limits of proportionality, the ratio of tangential stress to the shearing strain is called the modulus of rigidity of the material of the body and is denoted by η

i.e. η = `"Shearing stress"/"Shearing strain"`
In this case, the shape of a body changes but its volume remains unchanged.
Consider a cube of material fixed at its lower face and acted upon by a tangential force F at its upper surface having area A.
Only solids can exhibit a shearing as these have a definite shape.
In liquids, η = 0
So, the frictional (viscous) force cannot exist in the case of an ideal fluid and since they cannot sustain shearing stress or tangential forces are zero, there is no stress developed.
APPEARS IN
संबंधित प्रश्न
A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Figure. The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively. At what point along the rod should a mass m be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires.

The ratio stress/strain remain constant for small deformation of a metal wire. When the deformation is made larger, will this ratio increase or decrease?
When the skeleton of an elephant and the skeleton of a mouse are prepared in the same size, the bones of the elephant are shown thicker than those of the mouse. Explain why the bones of an elephant are thicker than proportionate. The bones are expected to withstand the stress due to the weight of the animal.
When some wax is rubbed on a cloth, it becomes waterproof. Explain.
A wire can sustain the weight of 20 kg before breaking. If the wire is cut into two equal parts, each part can sustain a weight of
A heave uniform rod is hanging vertically form a fixed support. It is stretched by its won weight. The diameter of the rod is
When a metal wire is stretched by a load, the fractional change in its volume ∆V/V is proportional to
A load of 10 kg is suspended by a metal wire 3 m long and having a cross-sectional area 4 mm2. Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is 2.0 × 1011 N m−2.
Answer in one sentence.
How should be a force applied on a body to produce shearing stress?
A spring is stretched by applying a load to its free end. The strain produced in the spring is ______.
Consider two cylindrical rods of identical dimensions, one of rubber and the other of steel. Both the rods are fixed rigidly at one end to the roof. A mass M is attached to each of the free ends at the centre of the rods.
Is stress a vector quantity?
If 'S' is stress and 'Y' is young's modulus of the material of a wire, the energy stored in the wire per unit volume is ______.
The area of the cross-section of the rope used to lift a load by a crane is 2.5 × 10-4m2. The maximum lifting capacity of the crane is 10 metric tons. To increase the lifting capacity of the crane to 25 metric tons, the required area of cross-section of the rope should be ______.
(take g = 10 ms-2)
What is an elastomer?
The SI unit of stress is:
What are the dimensions of strain?
