Question

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate the mass of salt formed.

Answer 1

Mass of Mn = 54.93

Mass of Cl = 35.45

Cl₂ = 35.45 × 2 = 70.9

∴ 1 mole MnCl₂ weighs = 54.93 + 70.9

= 125.83 g ≈ 126 g

So, 0.02 mole MnCl₂ will weigh = `126/1` × 0.02 g 

= 2.52 g