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प्रश्न
Magnesium and oxygen combine in the ratio of 3 : 2 by mass to form magnesium oxide. What mass of oxygen gas would be required to react completely with 24 g of magnesium ?
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उत्तर
Magnesium reacts with oxygen in the ratio of 3:2 to form magnesium oxide.
The above relation states that magnesium and oxygen combine in a fixed ratio of 3:2 by mass.
Therefore, 3g of magnesium react with 2g of oxygen to form magnesium oxide.
1g of magnesium requires = 2/3g of oxygen = 0.66g of oxygen
24g of magnesium require = 24 × 0.66g of oxygen = 16g
16g of oxygen would be required to react completely with 24g of magnesium.
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Match the names of ions and radicals from 1 to 10 with their correct answer from A to Q.
| Column A | Column B |
| 1. Hypochlorite | A: Hg2+ |
| 2. Permanganate | B: \[\ce{MnO_4^1-}\] |
| 3. Plumbous | C: Sn4+ |
| 4. Zincate | D: Pb2+ |
| 5. Nitride | E: Sn2+ |
| 6. Mercuric | F: Pb4+ |
| 7. Stannic | G: \[\ce{SO_3^2-}\] |
| 8. Nitrite | H: N3- |
| 9. Sulphite | I: \[\ce{NO_2^1-}\] |
| 10. Dichromate | J: \[\ce{MnO_4^2-}\] |
| K: Hg1+ | |
| L: \[\ce{SO_4^2-}\] | |
| M: CIO1- | |
| N: \[\ce{ZnO_2^2-}\] | |
| O: \[\ce{Cr_2O_7^2-}\] | |
| P: \[\ce{CrO_4^2-}\] | |
| Q: \[\ce{ClO_3^1-}\] |
