मराठी

Let C Be a Curve Defined Parametrically as X = a Cos 3 θ , Y = a Sin 3 θ , 0 ≤ θ ≤ π 2 . Determine a Point P on C, Where the Tangent to C is Parallel to the Chord Joining the Points (A, 0) and (0, A)

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प्रश्न

Let C be a curve defined parametrically as \[x = a \cos^3 \theta, y = a \sin^3 \theta, 0 \leq \theta \leq \frac{\pi}{2}\] . Determine a point P on C, where the tangent to C is parallel to the chord joining the points (a, 0) and (0, a).

बेरीज
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उत्तर

let point be p(x,y)

Given equation 

x = a cos3θ 

y = asin3θ

Slope of tangent = `"dy"/"dx"`

`"dx"/"dθ" = -3a cos^2θ sinθ`  

`"dy"/"dθ" = 3a sin^2θ cosθ`

∴ `"dy"/"dx" = (dy/(dθ))/(dx/(dθ)) = (3a sin^2θ cosθ)/(-3a cos^2θ sinθ) = -tanθ`      (∴ slope of tangent)

∴ Given two point (a ,0) and (0 , a)

∴ Slope of chord , m = `(y_2 - y_1)/(x_2 - x_1) = (a - 0)/(0 - a) = a/-a = -1`

∵ It is given that tangent to C is parallel to chord 

∴ slope of tangent = slope of chord

⇒ -tanθ = -1

θ = `pi/4`

∴ `x = a cos^3θ`

x = `a cos^3(pi/4)`

`x = a(1/sqrt (2))^3 = a/(2 sqrt(2))`

`y = a sin^3θ`

`y = a sin^3 (pi/4)`

`y = a(1/sqrt (2))^3 = a/(2 sqrt(2))`

∴ Point P is `(a/(2 sqrt(2)) , a/(2 sqrt(2)))`

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पाठ 14: Mean Value Theorems - Exercise 15.2 [पृष्ठ १८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 14 Mean Value Theorems
Exercise 15.2 | Q 10 | पृष्ठ १८

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