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प्रश्न
Integrate the following functions with respect to x :
(2x – 5)(3x + 4x)
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उत्तर
`int (2x - 5)(3x + 4x) "d"x`
= `int (72x + 8x^2 - 180 - 20x) "d"x`
= `int 72x "d"x + int 82x^2 "d"x - int 180 "d"x - int 20x "d"x`
= `72intx "d"x + 8intx^2 "d"x - 180int "d"x - 20 intx "d"x`
= `72 xx x^2/2 + 8 x^3/3 - 180x - 20 xx x^2/2 + "c"`
= `36x^2 + 8/3 x^3 - 180x - 10x^2 + "c"`
= `26x^2 + 8/3 x^3 - 180x + "c"`
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