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Integrate the following with respect to x: x sin 3x

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प्रश्न

Integrate the following with respect to x:

x sin 3x

बेरीज
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उत्तर

`int x sin 3x  "d"x`

`int "u"  "dv" = "uv" - "u""'""v"_1 + "u""'""v"_2 - "u""'""v"_3  +`  ..........(1)

u = x

u' = 1

u" = 0

v1 = `int "v"  "d"x``

= `int - (cos 3x)/3`

= `- 1/3 xx (sin 3x)/3`

v2 = `int "v"_1  "d"x`

= `int - 1/3^2  sin3x * "d"x`

= `- 1/3^2 xx 1/3 xx - cos 3x`

= `1/3^2  cos 3x`

`int x sin x  "d"x = x xx  - (cos3x)/3 - 1 xx - 1/3^2  sin 3x + 0  xx 1/3^3  cos3x + "c"`

`int x  sin  3x  "d"x = - x/3  cos 3x + 1/9  sin  3x + "c"`

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पाठ 11: Integral Calculus - Exercise 11.7 [पृष्ठ २१०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 11 Integral Calculus
Exercise 11.7 | Q 1. (i) | पृष्ठ २१०

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