Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
The gradient (slope) of a curve at any point (x, y) is `(x^2 - 4)/x^2`. If the curve passes through the point (2, 7), then the equation of the curve is
पर्याय
y = `x + 4/x + 3`
y = `x + 4/x + 4`
y = x2 + 3x + 4
y = x2 – 3x + 6
Advertisements
उत्तर
y = `x + 4/x + 3`
APPEARS IN
संबंधित प्रश्न
Evaluate:`int(tansqrtx)/sqrtxdx`
Integrate the following functions with respect to x :
`(x^3 + 4x^2 - 3x + 2)/x^2`
Integrate the following functions with respect to x :
`(3 + 4cosx)/(sin^2x)`
Integrate the following functions with respect to x :
`(sin^2x)/(1 + cosx)`
Integrate the following functions with respect to x :
cos 3x cos 2x
Integrate the following functions with respect to x :
sin2 5x
Integrate the following functions with respect to x :
`1/(sqrt(x + 3) - sqrt(x - 4))`
Integrate the following with respect to x :
`(sin sqrt(x))/sqrt(x)`
Integrate the following with respect to x :
`cot x/(log(sin x))`
Integrate the following with respect to x :
`tan x sqrt(sec x)`
Integrate the following with respect to x:
x log x
Integrate the following with respect to x:
x2 cos x
Integrate the following with respect to x:
`"e"^("a"x) cos"b"x`
Find the integrals of the following:
`1/(6x - 7 - x^2)`
Find the integrals of the following:
`1/sqrt(xx^2 + 4x + 2)`
Integrate the following with respect to x:
`(x + 2)/sqrt(x^2 - 1)`
Integrate the following functions with respect to x:
`sqrt(x^2 + 2x + 10)`
Choose the correct alternative:
`int (sec^2x)/(tan^2 x - 1) "d"x`
Choose the correct alternative:
`int "e"^(- 7x) sin 5x "d"x` is
