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प्रश्न
Integrate the following functions with respect to x :
`[sqrt(x) + 1/sqrt(x)]^2`
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उत्तर
`[sqrt(x) + 1/sqrt(x)]^2 = int[(sqrt(x))^2 + 2sqrt(x) xx 1/sqrt(x) + (1/sqrt(x))^2] "d"x`
= `int [x + 2 + 1/x] "d"x`
= `int x "d"x + int 2 "d"x + int 1/x "d"x`
= `int x "d"x + 2int "d"x + int 1/x "d"x`
= `x^2/2 + 2x + log |x| + "c"`
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