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प्रश्न
Integrate the following functions with respect to x :
cos 3x cos 2x
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उत्तर
`int cos 3x cos 2x "d"x = int 1/2 (2 cos 3x cos 2x) "d"x`
= `1/2 int [cos(3x + 2x) + cos(3x - 2x)] "d"x`
= `1/2 int (cos 5x + cos x) "d"x`
= `1/2 [int cos 5x "d"x + int cos x "d"x]`
= `1/2 [(sin 5x)/5 + sin x] + "c"`
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