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प्रश्न
In the presence of peroxide addition of HBr to propene takes place according to anti Markovnikov’s rule but peroxide effect is not seen in the case of HCl and HI. Explain.
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उत्तर
The bond energy of HCl is higher than that of HBr thus it is not cleaved by free radical mechanism to exhibit peroxide effect. However in case of HI the bond energy is so low that the iodine radical forms readily and after formation it combines to form an iodine molecule.
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संबंधित प्रश्न
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The addition of HBr to 1-butene gives a mixture of products A, B and C
| (A) |  |
| (B) |  |
| (C) | CH3 – CH2 – CH2 – CH2 – Br |
The mixture consists of:
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| (i) | CH3 – CH = CH – CH3 |
| (ii) | \[\begin{array}{cc} \ce{CH3 - C - CH = CH2}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) |  |
| (iv) | \[\begin{array}{cc} \phantom{...................}\ce{CH3}\\ \phantom{..............}/\\ \ce{(CH3)2 C = C}\\ \phantom{..............}\backslash\\ \phantom{...................}\ce{CH3} \end{array}\] |
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(II) HBO
(III) oxymercuration-demercuration
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