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प्रश्न
In the presence of peroxide addition of HBr to propene takes place according to anti Markovnikov’s rule but peroxide effect is not seen in the case of HCl and HI. Explain.
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उत्तर
The bond energy of HCl is higher than that of HBr thus it is not cleaved by free radical mechanism to exhibit peroxide effect. However in case of HI the bond energy is so low that the iodine radical forms readily and after formation it combines to form an iodine molecule.
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संबंधित प्रश्न
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Pent-2-ene
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Hexyne
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Arrange the following hydrogen halides in order of their decreasing reactivity with propene.
An alkene 'X' on ozonolysis produces two moles of isovaleraldehyde. Predict the IUPAC name of the alkene.
Which of the following reagent is used for the following reaction?
\[\ce{CH3CH2CH3 ->[?] CH3CH2CHO}\]
The major product formed in the following reactions is:
Select schemes A, B, C out of
(I) acid catalysed hydration
(II) HBO
(III) oxymercuration-demercuration
Propene, \[\ce{CH3 - CH = CH2}\] can be converted to 1-propanol by oxidation. Which set of reagents among the following is ideal to effect the conversion ______.
3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is ______.
In the presence of peroxide, HCl and HI do not give anti-Markovnikov's addition of alkenes because ______.
Identify the correct reagents that would bring about the following transformation.
