मराठी

In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to

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प्रश्न

In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to

पर्याय

  • ΔEFC

  • ΔECF

  • ΔCEF

  • ΔFEC

MCQ
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उत्तर

ΔFEC

Explanation:

It is given that

In the figure, AB ⊥ BE, FE ⊥ BE

Now, BC = DE.

Adding DC to both the sides, we get,

⇒ BC + DC = DE + DC

⇒ BD = CE

In ΔABD and ΔCEF

BD = CE (Proved)

AB = FE (Given)

∠ABD = ∠FEC (Each 90°)

∴ ΔABD ≅ ΔFEC by SAS congruence rule.

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पाठ 12: Congruent Triangles - Exercise 12.8 [पृष्ठ ८६]

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आर.डी. शर्मा Mathematics [English] Class 9
पाठ 12 Congruent Triangles
Exercise 12.8 | Q 13 | पृष्ठ ८६

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