मराठी

In the Following Figure, De is Parallel to Bc. Show That: (I) Area ( δAdc ) = Area( δAeb ). (Ii) Area ( δBod ) = Area( δCoe ). - Mathematics

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प्रश्न

In the following figure, DE is parallel to BC.
Show that: 
(i) Area ( ΔADC ) = Area( ΔAEB ).
(ii) Area ( ΔBOD ) = Area( ΔCOE ).

बेरीज
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उत्तर

(i) In ΔABC, D is the midpoint of AB and E is the midpoint of AC.
`"AD"/"AB" = "AE"/"AC"`

DE is parallel to BC.
∴ A( ΔADC ) = A( ΔBDC ) = `1/2` A( ΔABC )
Again,
∴ A( ΔAEB ) = A( ΔBEC ) = `1/2` A( ΔABC )

From the above two equations, we have
Area( ΔADC ) = Area( ΔAEB ).
Hence Proved.

(ii) We know that the area of triangles on the same base and between the same parallel lines are equal.
Area( ΔDBC )= Area( ΔBCE )
Area( ΔDOB ) + Area( ΔBOC ) = Area( ΔBOC ) + Area( ΔCOE )
So, Area( ΔDOB ) = Area( ΔCOE ).

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Figures Between the Same Parallels
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Area Theorems [Proof and Use] - Exercise 16 (A) [पृष्ठ १९७]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 16 Area Theorems [Proof and Use]
Exercise 16 (A) | Q 11 | पृष्ठ १९७
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