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प्रश्न
ABCD and BCFE are parallelograms. If area of triangle EBC = 480 cm2; AB = 30 cm and BC = 40 cm.
Calculate :
(i) Area of parallelogram ABCD;
(ii) Area of the parallelogram BCFE;
(iii) Length of altitude from A on CD;
(iv) Area of triangle ECF.
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उत्तर
(i) Since ΔEBC and parallelogram ABCD are on the same base BC and between the same parallels i.e. BC // AD.
∴ A( ΔEBC ) = `1/2` x A( parallelogram ABCD )
parallelogram ABCD = 2 x A( ΔEBC )
= 2 x 480 cm2
= 960 cm2
(ii) Parallelograms on same base and between same parallels are equal in area.
Area of BCFE = Area of ABCD = 960 cm2
(iii) Area of triangle ACD=480 = `1/2` x 30 x Altitude
Altitude = 32 cm
(iv) The area of a triangle is half that of a parallelogram on the same base and between the same parallels.
Therefore,
Area( ΔECF ) = `1/2` Area(`square`CBEF )
Similarly, Area( ΔBCE ) = `1/2`Area(`square`CBEF )
⇒ Area( ΔECF ) = Area( ΔBCE ) = 480 cm2.
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In parallelogram ABCD, E is a point in AB and DE meets diagonal AC at point F. If DF: FE = 5:3 and area of ΔADF is 60 cm2; find
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Show that:
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