मराठी

In the Following Figure, Ce is Drawn Parallel to Diagonals Db of the Quadrilateral Abcd Which Meets Ab Produced at Point E. Prove that δAde and Quadrilateral Abcd Are Equal in Area - Mathematics

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प्रश्न

In the following figure, CE is drawn parallel to diagonals DB of the quadrilateral ABCD which meets AB produced at point E.
Prove that ΔADE and quadrilateral ABCD are equal in area.

बेरीज
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उत्तर

Since ΔDCB and ΔDEB are on the same base DB and between the same parallels i.e. DB // CE, therefore we get

Ar. ( ΔDCB) = Ar. ( ΔDEB )
Ar. ( ΔDCB + ΔADB ) = AR. (ΔDEB + ΔADB )
Ar. ( ABCD ) = Ar. ( ΔADE )
Hence proved.

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Figures Between the Same Parallels
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Area Theorems [Proof and Use] - Exercise 16 (A) [पृष्ठ १९६]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 16 Area Theorems [Proof and Use]
Exercise 16 (A) | Q 6 | पृष्ठ १९६

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