Advertisements
Advertisements
प्रश्न
In the following figure, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to ______.
पर्याय
30º
45º
60º
120º
Advertisements
उत्तर
In the following figure, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to 60º.
Explanation:
Given: BC is a diameter of the circle and ∠BAO = 60º.
Now, in triangle OAB,
OA = OB ...[Radii of the same circle]
So, ∠ABO = ∠BAO ...[Angle opposite to equal sides are equal]
∠ABO = ∠BAO = 60º ...[Given]
Now, ∠ADC = ∠ABC = 60º ...[∠ADC and ∠ABC are angles in the same segment of a circle are equal]
Therefore, ∠ADC = 60º.
APPEARS IN
संबंधित प्रश्न
The perimeter (in cm) of a square circumscribing a circle of radius a cm, is
AB is a chord of a circle with centre O , AOC is a diameter and AT is the tangent at A as shown in Fig . 10.70. Prove that \[\angle\]BAT = \[\angle\] ACB.
The point of concurrence of all angle bisectors of a triangle is called the ______.
If O is the centre of the circle, find the value of x in each of the following figures
Draw a circle of radius 6 cm. In the circle, draw a chord AB = 6 cm.
(i) If O is the center of the circle, join OA and OB.
(ii) Assign a special name to ∆AOB
(iii) Write the measure of angle AOB.
Find the diameter of the circle
Radius = 10 cm
Find the diameter of the circle
Radius = 6 cm
If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is ______.
On a common hypotenuse AB, two right triangles ACB and ADB are situated on opposite sides. Prove that ∠BAC = ∠BDC.
From the figure, identify a segment.
