Advertisements
Advertisements
प्रश्न
In the following figure, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to ______.

विकल्प
30º
45º
60º
120º
Advertisements
उत्तर
In the following figure, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to 60º.
Explanation:
Given: BC is a diameter of the circle and ∠BAO = 60º.
Now, in triangle OAB,
OA = OB ...[Radii of the same circle]
So, ∠ABO = ∠BAO ...[Angle opposite to equal sides are equal]
∠ABO = ∠BAO = 60º ...[Given]
Now, ∠ADC = ∠ABC = 60º ...[∠ADC and ∠ABC are angles in the same segment of a circle are equal]
Therefore, ∠ADC = 60º.
APPEARS IN
संबंधित प्रश्न
Fill in the blanks:
Segment of a circle is the region between an arc and __________ of the circle.
Write True or False. Give reason for your answer.
Line segment joining the centre to any point on the circle is a radius of the circle.
Two tangent segments PA and PB are drawn to a circle with center O such that ∠APB = 120°. Prove that OP = 2AP
In the given figure, PO \[\perp\] QO. The tangents to the circle at P and Q intersect at a point T. Prove that PQ and OTare right bisector of each other.

Draw circle with the radii given below.
4 cm
The length of the tangent from point A to a circle, of radius 3 cm, is 4 cm. The distance of A from the centre of the circle is ______
If a hexagon ABCDEF circumscribe a circle, prove that AB + CD + EF = BC + DE + FA.
A quadrilateral ABCD is inscribed in a circle such that AB is a diameter and ∠ADC = 130º. Find ∠BAC.
In the following figure, O is the centre of the circle, ∠BCO = 30°. Find x and y.

From the figure, identify a diameter.
