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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

In the case of bond formation in Acetylene molecule: How many covalent bonds are formed?

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प्रश्न

In the case of bond formation in Acetylene molecule: How many covalent bonds are formed?

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उत्तर

In the acetylene molecule, there are five covalent bonds.

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पाठ 5: Chemical Bonding - Exercises [पृष्ठ ७९]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 5 Chemical Bonding
Exercises | Q 3. (M)(a) | पृष्ठ ७९

संबंधित प्रश्‍न

Select and write the most appropriate alternatives from the given choices.

The angle between the two covalent bonds is minimum in:


Give a reason for HF is a polar molecule


Write the geometry and bond angle present in ammonia.


F-Be-F is a liner molecule but H-O-H is angular. Explain.


In the case of bond formation in Acetylene molecule: State number of sigma and pi bonds formed.


In the case of bond formation in Acetylene molecule: Name the type of Hybridization.


Define Bond Length


Predict the shape and bond angles in the following molecule:

CF4


Predict the shape and bond angles in the following molecule:

NF3


Predict the shape and bond angles in the following molecule:

HCN


Predict the shape and bond angles in the following molecule:

H2S


Complete the flow chart.

Molecular Formula Structural Formula Shape/ Geometry Bond angle
BeCl2     180°
  O=C=O Linear  
C2H2      

Write the formula to calculate the bond order of molecule.


Energy required to dissociate 6 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C. Bond energy of H-H bond will be ____________.


The CORRECT order of C-X bond polarity is ____________.


What is the value of C-O-H bond angle in CH3_OH?


Which of following bonds has maximum bond length?


The hybridization and bond angle in BeCl2 molecule are ____________ respectively.


Which of the following pairs have identical bond order?


Identify the CORRECT option.


Which of the following is INCORRECTLY matched?


Why is bond order of Be2 molecule zero?

(Nb = bonding electrons, Na = antibonding electrons)


Consider the ions/molecule:

\[\ce{O^+_2, O_2, O^-_2, O^{2-}_2}\]

For increasing bond order the correct option is:


What is the bona order of O2 molecules?


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