Advertisements
Advertisements
प्रश्न
In quadrilateral HOPE, the pairs of opposite sides are ______.
Advertisements
उत्तर
In quadrilateral HOPE, the pairs of opposite sides are EH, PO and HO, EP.
Explanation:
EH, PO and HO, EP are the opposite sides because they have no common vertices.
APPEARS IN
संबंधित प्रश्न
Complete of the following, so as to make a true statement:
In a quadrilateral the point of intersection of the diagonals lies in .... of the quadrilateral.
The sum of the interior angles of a polygon is three times the sum of its exterior angles. Determine the number of sided of the polygon.
Two angles of a quadrilateral are 68° and 76°. If the other two angles are in the ratio 5 : 7; find the measure of each of them.
ABCDE is a regular pentagon. The bisector of angle A of the pentagon meets the side CD in point M. Show that ∠AMC = 90°.
Observe the figure below and find out their name.
One angle of a hexagon is 140° and the remaining angles are in the ratio 4 : 3 : 4 : 5 : 4. Calculate the measures of the smallest and the largest angles.
If one angle of a cyclic quadrilateral is 75°, then the opposite angle is
Using the information given, name the right angles in part of figure:
BA ⊥ BD
Using the information given, name the right angles in part of figure:
AE ⊥ CE
What conclusion can be drawn from part of given figure, if BD bisects ∠ABC?
