Advertisements
Advertisements
प्रश्न
Construct a quadrilateral NEWS in which NE = 7 cm, EW = 6 cm, ∠N = 60°, ∠E = 110° and ∠S = 85°.
Advertisements
उत्तर
Fourth angle = 360° – (60° + 110° + 85°)
= 360° – 255°
= 105°
Steps of construction:
Step I: Draw NE = 7 cm.
Step II: Make ∠NEX = 110°
Step III: With E as centre and radius 6 cm, draw an arc, cutting EX at W.
Step IV: Make ∠EWY = 105°
Step V: Make ∠ENZ = 60°, so that NZ and WY intersect each other at point S.
Hence, NEWS is the required quadrilateral.
APPEARS IN
संबंधित प्रश्न
How many diagonals does following have?
A regular hexagon
A quadrilateral has all its four angles of the same measure. What is the measure of each?
The four angles of a quadrilateral are as 3 : 5 : 7 : 9. Find the angles.
In Fig. 16.21, the bisectors of ∠A and ∠B meet at a point P. If ∠C = 100° and ∠D = 50°, find the measure of ∠APB.
Given : In quadrilateral ABCD ; ∠C = 64°, ∠D = ∠C – 8° ; ∠A = 5(a+2)° and ∠B = 2(2a+7)°.
Calculate ∠A.
In the given figure : ∠b = 2a + 15 and ∠c = 3a + 5; find the values of b and c.
If APB and CQD are two parallel lines, then the bisectors of the angles APQ, BPQ, CQP and PQD form ______.
What conclusion can be drawn from part of given figure, if DC is the bisector of ∠ADB, CA ⊥ DA and CB ⊥ DB?
Draw a rough sketch of a quadrilateral PQRS. Draw its diagonals. Name them. Is the meeting point of the diagonals in the interior or exterior of the quadrilateral?
Draw a rough sketch of a quadrilateral KLMN. State two pairs of opposite angles.
