Advertisements
Advertisements
प्रश्न
In quadrilateral HOPE, the pairs of opposite sides are ______.
Advertisements
उत्तर
In quadrilateral HOPE, the pairs of opposite sides are EH, PO and HO, EP.
Explanation:

EH, PO and HO, EP are the opposite sides because they have no common vertices.
APPEARS IN
संबंधित प्रश्न
In a quadrilateral, define of the following Interior .
If the sum of the two angles of a quadrilateral is 180°. What is the sum of the remaining two angles?
The sides of a quadrilateral are produced in order. What is the sum of the four exterior angles?
In Fig. 16.21, the bisectors of ∠A and ∠B meet at a point P. If ∠C = 100° and ∠D = 50°, find the measure of ∠APB.

Complete the following statement by means of one of those given in brackets against each:
If opposite angles of a quadrilateral are equal, then it is necessarily a ....................
Given : In quadrilateral ABCD ; ∠C = 64°, ∠D = ∠C – 8° ; ∠A = 5(a+2)° and ∠B = 2(2a+7)°.
Calculate ∠A.
ABCDE is a regular pentagon. The bisector of angle A of the pentagon meets the side CD in point M. Show that ∠AMC = 90°.
Two opposite angles of a parallelogram are 100° each. Find each of the other two opposite angles.
Observe the figure below and find out their name.

Can we have two obtuse angles whose sum is a reflex angle? Why or why not?
