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प्रश्न
In Fig. 5, from a cuboidal solid metallic block, of dimensions 15cm ✕ 10cm ✕ 5cm, a cylindrical hole of diameter 7 cm is drilled out. Find the surface area of the remaining block [Use
`pi=22/7`]
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उत्तर
Surface area of the remaining block = Surface area of the cuboid + Curved surface area of cylinder − 2 × Area of base of cylinder
`=2(15xx10xx+10xx5+15xx5)+(2xx22/7xx7/2xx5)-(2xx22/7xx7/2xx7/2)`
= 583 cm2
Thus, the surface area of the remaining block is 583 cm2.
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Khurja is a city in the Indian state of Uttar Pradesh famous for the pottery. Khurja pottery is traditional Indian pottery work which has attracted Indians as well as foreigners with a variety of tea sets, crockery and ceramic tile works. A huge portion of the ceramics used in the country is supplied by Khurja and is also referred as "The Ceramic Town". One of the private schools of Bulandshahr organised an Educational Tour for class 10 students to Khurja. Students were very excited about the trip. Following are the few pottery objects of Khurja.
Students found the shapes of the objects very interesting and they could easily relate them with mathematical shapes viz sphere, hemisphere, cylinder etc. |
Maths teacher who was accompanying the students asked the following questions:
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3 cubes each of 8 cm edge are joined end to end. Find the total surface area of the cuboid.
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Statement R( Reason): Top is obtained by joining the plane surfaces of the hemisphere and cone together.
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