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A Solid Wooden Toy is in the Form of a Hemisphere Surrounded by a Cone of Same Radius. the Radius of Hemisphere is 3.5 Cm and the Total Wood Used in the Making of Toy is 1 - Mathematics

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प्रश्न

A solid wooden toy is in the form of a hemisphere surrounded by a cone of same radius. The radius of hemisphere is 3.5 cm and the total wood used in the making of toy is 166 `5/6`  cm3. Find the height of the toy. Also, find the cost of painting the hemispherical part of the toy at the rate of Rs 10 per cm2 .[Use`pi=22/7`]

थोडक्यात उत्तर
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उत्तर

Let h be the height of the cone and r be the radius of the base of cone.

The volume of the wooden toy = `1/3pir^2h+2/3pir^3`

`=1/3pir^2(h+2r)`

`=1/3xx22/7xx3.5xx3.5(h+7)`

`=77/6(h+7)`

 According to the question,

 `77/6(h+7)=166`

`=>77/6(h+7)=1001/6`

 h=6

The height of the wooden toy = 6 cm + 3.5 cm  = 9.5 cm

Now,

Curved surface area of the hemispherical part = `2xx22/7xx3.5xx3.5 = 77 cm^2`

 Hence, the cost of painting the hemispherical part of the toy = 77×10  = Rs 770

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पाठ 14: Surface Areas and Volumes - Exercise 14.2 [पृष्ठ ६२]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 14 Surface Areas and Volumes
Exercise 14.2 | Q 32 | पृष्ठ ६२

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