Advertisements
Advertisements
प्रश्न
In a trapezium ABCD, side AB is parallel to side DC. If ∠A = x° and ∠D = (3x – 20)°; find the value of x.
Advertisements
उत्तर
∵ AB || DC and BC is transversal
∴ ∠A and ∠B are Co-interior angles with their sum = 180°
i.e. ∠A + ∠D = 180°
⇒ x° + (3x – 20)° = 180°
⇒ x° + 3x° – 20° = 180°
⇒ 4x° = 180° + 20°
x° = `200/4` = 50°
∴ Value of x = 50°
APPEARS IN
संबंधित प्रश्न
In a quadrilateral, define of the following Opposite sides .
In Fig. 16.19, ABCD is a quadrilateral.
How many pairs of adjacent angles are there?
In the given figure, PQRS is an isosceles trapezium. Find x and y.
If the bisectors of two adjacent angles A and B of a quadrilateral ABCD intersect at a point O such that ∠C + ∠D = k ∠AOB, then find the value of k.
Write two conditions that will make the adjoining figure a square.
If APB and CQD are two parallel lines, then the bisectors of the angles APQ, BPQ, CQP and PQD form ______.
D and E are the mid-points of the sides AB and AC respectively of ∆ABC. DE is produced to F. To prove that CF is equal and parallel to DA, we need an additional information which is ______.
In the following figure,
∠COA is a/an ______ angle
The number of right angles in a straight angle is ______ and that in a complete angle is ______.
Draw a rough sketch of a quadrilateral PQRS. Draw its diagonals. Name them. Is the meeting point of the diagonals in the interior or exterior of the quadrilateral?
