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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

If the function f(x) = 7x-3, x ∈ R, x ≠ 0 is a decreasing function, then x ∈ ______

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प्रश्न

If the function f(x) = `7/x - 3`, x ∈ R, x ≠ 0 is a decreasing function, then x ∈ ______

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उत्तर

If the function f(x) = `7/x - 3`, x ∈ R, x ≠ 0 is a decreasing function, then x ∈ R - {0}

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पाठ 1.4: Applications of Derivatives - Q.2

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

Test whether the function is increasing or decreasing. 

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Find the intervals in which the function f given by f(x) = 2x3 − 3x2 − 36x + 7 is

  1. Strictly increasing
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Show that the function f given by f(x) = 10x is increasing for all x ?


Find the value(s) of a for which f(x) = x3 − ax is an increasing function on R ?


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 Prove that the function `f(x) = x^3- 6x^2 + 12x+5` is increasing on R. 


Show that y = `log (1 + x) – (2x)/(2 + x), x > - 1` is an increasing function on its domain.


Test whether the following function is increasing or decreasing.

f(x) = `7/"x" - 3`, x ∈ R, x ≠ 0


Let f(x) = x3 − 6x2 + 9𝑥 + 18, then f(x) is strictly decreasing in ______


Show that the function f(x) = `(x - 2)/(x + 1)`, x ≠ – 1 is increasing


By completing the following activity, find the values of x such that f(x) = 2x3 – 15x2 – 84x – 7 is decreasing function.

Solution: f(x) = 2x3 – 15x2 – 84x – 7

∴ f'(x) = `square`

∴ f'(x) = 6`(square) (square)`

Since f(x) is decreasing function.

∴ f'(x) < 0

Case 1: `(square)` > 0 and (x + 2) < 0

∴ x ∈ `square`

Case 2: `(square)` < 0 and (x + 2) > 0

∴ x ∈ `square`

∴ f(x) is decreasing function if and only if x ∈ `square`


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f(n) = `{{:(1/2(n + 1), "If n is sold"),(1/2n, "if n is even"):}` is


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The function f(x) = x3 + 3x is increasing in interval ______.


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After the domain has been divided into intervals, which quantity must be determined in each interval?


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