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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

If sinθ = 1161, then find the value of cosθ using the trigonometric identity. - Geometry Mathematics 2

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प्रश्न

If sinθ = `11/61`, then find the value of cosθ using the trigonometric identity.

बेरीज
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उत्तर

Given: sinθ = `11/61`

We know that,

sin2θ + cos2θ = 1

∴ `(11/61)^2 + cos^2θ` = 1

∴ `121/3721 + cos^2θ` = 1

∴ cos2θ = `1 - 121/3721`

∴ cos2θ = `(3721 - 121)/3721`

∴ cos2θ = `3600/3721`

∴ cosθ = `60/61`  .......[Taking square root of both sides]

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2021-2022 (March) Set 1

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संबंधित प्रश्‍न

Prove the following trigonometric identities:

`(\text{i})\text{ }\frac{\sin \theta }{1-\cos \theta }=\text{cosec}\theta+\cot \theta `


Prove that (1 + cot θ – cosec θ)(1+ tan θ + sec θ) = 2


Prove the following trigonometric identities.

sec A (1 − sin A) (sec A + tan A) = 1


Prove the following trigonometric identities.

`cos A/(1 - tan A) + sin A/(1 - cot A)  = sin A + cos A`


Prove the following trigonometric identities.

(1 + cot A − cosec A) (1 + tan A + sec A) = 2


Prove the following trigonometric identities.

tan2 A sec2 B − sec2 A tan2 B = tan2 A − tan2 B


Prove the following identities:

`tan A - cot A = (1 - 2cos^2A)/(sin A cos A)`


Prove the following identities:

`sinA/(1 - cosA) - cotA = cosecA`


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`cot^2A((secA - 1)/(1 + sinA)) + sec^2A((sinA - 1)/(1 + secA)) = 0`


If tan A = n tan B and sin A = m sin B, prove that:

`cos^2A = (m^2 - 1)/(n^2 - 1)`


`1/((1+ sin θ)) + 1/((1 - sin θ)) = 2 sec^2 θ`


If` (sec theta + tan theta)= m and ( sec theta - tan theta ) = n ,` show that mn =1


If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2?


Prove the following identity :

`(1 - cos^2θ)sec^2θ = tan^2θ`


Prove the following identity : 

`(1 + tan^2θ)sinθcosθ = tanθ`


Prove that `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec(90^circ - A) cosec(90^circ - A)`


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Choose the correct alternative:

1 + cot2θ = ? 


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