मराठी

If the Point P(X, Y ) is Equidistant from the Points A(5, 1) and B (1, 5), Prove that X = Y.

Advertisements
Advertisements

प्रश्न

If the point P(x, y ) is equidistant from the points A(5, 1) and B (1, 5), prove that x = y.

Advertisements

उत्तर

The distance d between two points `(x_1,y_1)` ``nd `(x_2,y_2)` is given by the formula

`d = sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)`

The three given points are P(x, y), A(5,1) and B(1,5).

Now let us find the distance between ‘P’ and ‘A’.

`PA = sqrt((x - 5)^2 + (y - 1)^2)`

Now, let us find the distance between ‘P’ and ‘B’.

`PB = sqrt((x - 1)^2 + (y - 5)^2)`

It is given that both these distances are equal. So, let us equate both the above equations,

PA = PB 

`sqrt((x - 5)^2 + (y -1)^2) = sqrt((x - 1)^2 + (y - 5)^2)`

Squaring on both sides of the equation we get,

`(x - 5)^2 + (y - 1)^2 = (x - 1)^2 + (y - 5)^2`

`=> x^2 + 25 - 10x + y^2 + 1 - 2y = x^2 + 1 - 2x + y^2 + 25 - 10y` 

`=> 26 - 10x - 2y = 26 - 10y - 2x`

`=> 10y - 2y = 10x - 2x`

`=> 8y = 8x`

=> y = x

Hence we have proved that x y.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-ordinate Geometry - Exercise 6.2 [पृष्ठ १६]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 10
पाठ 6 Co-ordinate Geometry
Exercise 6.2 | Q 33 | पृष्ठ १६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The x-coordinate of a point P is twice its y-coordinate. If P is equidistant from Q(2, –5) and R(–3, 6), find the coordinates of P.

 


Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).


If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?


Find the distance between the points

A(1,-3) and B(4,-6)


If P (x , y )  is equidistant from the points  A (7,1)  and B (3,5) find the relation between x and y


AB and AC are the two chords of a circle whose radius is r. If p and q are
the distance of chord AB and CD, from the centre respectively and if
AB = 2AC then proove that 4q2 = p2 + 3r2.


Find the distance between the following pair of point in the coordinate plane :

(5 , -2) and (1 , 5)


Find the distance of the following point from the origin :

(0 , 11)


A(-2, -3), B(-1, 0) and C(7, -6) are the vertices of a triangle. Find the circumcentre and the circumradius of the triangle. 


Prove that the points (0 , 2) , (1 , 1) , (4 , 4) and (3 , 5) are the vertices of a rectangle.


Prove that the points (0 , -4) , (6 , 2) , (3 , 5) and (-3 , -1) are the vertices of a rectangle.


Find the distance between the origin and the point:
(8, −15)


A point A is at a distance of `sqrt(10)` unit from the point (4, 3). Find the co-ordinates of point A, if its ordinate is twice its abscissa.


A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.


Prove that the points A (1, -3), B (-3, 0) and C (4, 1) are the vertices of an isosceles right-angled triangle. Find the area of the triangle.


The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.


Find distance CD where C(–3a, a), D(a, –2a).


Show that the point (0, 9) is equidistant from the points (–4, 1) and (4, 1).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×