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If log y = log (sin x) – x2, show that dydxd2ydx2+4xdydx+(4x2+3)y = 0. - Mathematics and Statistics

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प्रश्न

If log y = log (sin x) – x2, show that `(d^2y)/(dx^2) + 4x "dy"/"dx" + (4x^2 + 3)y` = 0.

बेरीज
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उत्तर

log y = log (sin x) – x2 
∴ log y = `log (sin x) – log e^(x^2)`

∴ log y = `log(sinx/e^(x^2))`

∴ y = `sinx/e^(x^2)`

∴ `e^(x^2).y` = sin x                     ...(1)
Differentiating both sides w.r.t. x, we get

`e^(x^2)."dy"/"dx" + y."d"/"dx"e^(x^2) = "d"/"dx"(sinx)`

∴ `e^(x^2)."dy"/"dx" + y.e^(x^2)."d"/"dx"(x^2)` = cos x

∴ `e^(x^2)."dy"/"dx" + y.e^(x^2) xx 2x` = cos x

∴ `e^(x^2)("dy"/"dx" + 2xy)` = cos x
Differentiating again w.r.t. x, we get

`e^(x^2)."d"/"dx"("dy"/"dx" + 2xy) + ("dy"/"dx" + 2xy)."d"/"dx"(e^(x^2)) = "d"/"dx"(cosx)`

∴ `e^(x^2)[(d^2y)/(dx^2) + 2(x"dy"/"dx" + y xx 1)] + ("dy"/"dx" + 2xy).e^(x^2)."d"/"dx"(x^2)` = – sin x

∴ `e^(x^2)[(d^2y)/(dx^2) + 2x"dy"/"dx" + y] + ("dy"/"dx" + 2xy).e^(x^2) xx 2x` = – sin x

∴ `e^(x^2)[(d^2y)/(dx^2) + 2x"dy"/"dx" + 2y + 2x"dy"/"dx" + 4x^2y]`

= `-e^(x^2).y`                ...[By (1)]

∴ `(d^2y)/(dx^2) + 4x"dy"/"dx" + 4x^2y + 2y` = – y

∴ `(d^2y)/(dx^2) + 4x"dy"/"dx" + 4x^2y + 2y + y` = 0

∴ `(d^2y)/(dx^2) + 4x"dy"/"dx" + 4x^2y + 3y` = 0

∴ `(d^2y)/(dx^2) + 4x"dy"/"dx" + (4x^2 + 3)y` = 0.

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पाठ 1: Differentiation - Miscellaneous Exercise 1 (II) [पृष्ठ ६४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 1 Differentiation
Miscellaneous Exercise 1 (II) | Q 7.2 | पृष्ठ ६४

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