Question

Find `bb(dy/dx)` in the following:

ax + by² = cos y

Answer 1

ax + by² = cos y

Differentiating both sides with respect to x,

⇒ `a d/dx (x) + b d/dx (y^2) = d/dx(cos y)`

⇒ `a xx 1 + b * 2y dy/dx = - sin y dy/dx`

⇒ `a + 2by dy/dx + sin y dy/dx = 0`

⇒ `a + dy/dx (2by +sin y) = 0`

⇒ `dy/dx (2by + sin y) = - a`

∴ `dy/dx = (-a)/(2by + sin y)`