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प्रश्न
Find `bb(dy/dx)` in the following:
xy + y2 = tan x + y
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उत्तर
xy + y2 = tan x + y
Differentiating both sides with respect to x,
⇒ `x d/dx (y) + y d/dx (x) + d/dx (y^2) = d/dx (tan x) + d/dx (y)`
⇒ `x dy/dx + y + 2y dy/dx = sec^2 x + dy/dx`
⇒ `dy/dx (x+ 2y - 1) = sec^2 x - y`
∴ `dy/dx = (sec^2 x - y)/(x + 2y - 1)`
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