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प्रश्न
Find `bb(dy/dx)` in the following:
2x + 3y = sin x
बेरीज
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उत्तर
2x + 3y = sin x
Differentiating both sides with respect to x,
⇒ `2 d/dx (x) + 3 d/dx (y) = d/dx(sin x)`
⇒ `2 xx 1 + 3 dy/dx = cos x`
⇒ `3 dy/dx = cos x - 2`
`dy/dx = (cos x - 2)/3`
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