मराठी

If A = [cosαsinα-sinαcosα], and A–1 = A′, find value of α

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प्रश्न

If A = `[(cosalpha, sinalpha),(-sinalpha, cosalpha)]`, and A–1 = A′, find value of α

बेरीज
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उत्तर

Here, A = `[(cosalpha, sinalpha),(-sinalpha, cosalpha)]`

Given that: A–1 = A′

Pre-multiplying both sides by A

AA–1 = AA′

⇒ I = AA′   ......[∵ AA–1 = I]

⇒ `[(1, 0),(0, 1)] = [(cosalpha, sinalpha),(-sinalpha, cosalpha)] [(cosalpha, - sinalpha),(sinalpha, cosalpha)]`

⇒ `[(1, 0),(0, 1)] = [(cos^2alpha + sin^2alpha, -sinalpha cosalpha + sinalpha cosalpha),(-sinalpha cosalpha + cosalpha sinalpha, sin^2alpha + cos^2alpha)]`

⇒ `[(1, 0),(0, 1)] = [(1, 0),(0,  1)]`

Hence, it is true for all values of a.

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पाठ 3: Matrices - Exercise [पृष्ठ ५८]

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