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If 3 sin A + 5 cos A = 5, then show that 5 sin A – 3 cos A = ± 3 - Geometry Mathematics 2

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प्रश्न

If 3 sin A + 5 cos A = 5, then show that 5 sin A – 3 cos A = ± 3

बेरीज
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उत्तर

3 sin A + 5 cos A = 5   ....[Given]

∴ (3 sin A + 5 cos A)2 = 25   ......[Squaring both the sides]

∴ 9 sin2A + 30 sin A cos A + 25 cos2A = 25

∴ 9(1 – cos2A) + 30 sin A cos A + 25(1 – sin2A) = 25

∴ 9 – 9 cos2A + 30 sin A cos A + 25 – 25 sin2A = 25

∴ 25 sin2A – 30 sin A cos A + 9 cos2A = 9

∴ (5 sin A – 3 cos A)2 = 9   ......[∵ a2 – 2ab + b2 = (a – b)2]

∴ 5 sin A – 3 cos A = ± 3   .....[Taking square root of both sides]

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