Advertisements
Advertisements
प्रश्न
If 2x - 3y = 10 and xy = 16; find the value of 8x3 - 27y3.
Advertisements
उत्तर
Given that 2x - 3y = 10, xy = 16
∴ (2x - 3y)3 = (10)3
⇒ 8x3 - 27y3 - 3 (2x) (3y) (2x - 3y) = 1000
⇒ 8x3 - 27 y3 -18xy (2x - 3y) = 1000
⇒ 8x3 - 27 y3 - 18 (16) (10) = 1000
⇒ 8x3 - 27 y3 - 2880 = 1000
⇒8x3 - 27 y3 = 1000 + 2880
⇒ 8x3 - 27 y3 =3880
APPEARS IN
संबंधित प्रश्न
Expand.
`(x + 1/x)^3`
Find the cube of : 5a + 3b
If a + 2b + c = 0; then show that: a3 + 8b3 + c3 = 6abc.
Use property to evaluate : 73 + 33 + (-10)3
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
- Sum of these numbers
- Difference of their cubes
- Sum of their cubes.
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
Evaluate the following :
(5.45)3 + (3.55)3
If `"a" + 1/"a"` = 6, then find the value of `"a"^3 + 1/"a"^3`
Expand (52)3
Find the volume of the cube whose side is (x + 1) cm
