Advertisements
Advertisements
प्रश्न
If 2x - 3y = 10 and xy = 16; find the value of 8x3 - 27y3.
योग
Advertisements
उत्तर
Given that 2x - 3y = 10, xy = 16
∴ (2x - 3y)3 = (10)3
⇒ 8x3 - 27y3 - 3 (2x) (3y) (2x - 3y) = 1000
⇒ 8x3 - 27 y3 -18xy (2x - 3y) = 1000
⇒ 8x3 - 27 y3 - 18 (16) (10) = 1000
⇒ 8x3 - 27 y3 - 2880 = 1000
⇒8x3 - 27 y3 = 1000 + 2880
⇒ 8x3 - 27 y3 =3880
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the cube of : 3a- 2b
Use property to evaluate : 133 + (-8)3 + (-5)3
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes.
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
If `5x + (1)/(5x) = 7`; find the value of `125x^3 + (1)/(125x^3)`.
If m - n = -2 and m3 - n3 = -26, find mn.
Expand: (3x + 4y)3.
Expand: (41)3
Expand (3p + 4q)3
